For the recurrence equation $$T(N)=aT(N/b)+f(N)$$, if $$af(N/b)=

For the recurrence equation $$T(N)=aT(N/b)+f(N)$$, if $$af(N/b)=f(N)$$, then $$T(N)=\Theta (f(N) log_b N)$$. ~@[](2)

答案：TRUE