PROGRAMMING:Calculation of semicircle area and arc length
Program and output semicircle arc length with radius r = 5.3 (hint: semicircle arc length should not add diameter length.) And the area of the semicircle enclosed by the semicircle and the straight meridian is 3.14159. The radius R and must be expressed by macro constants.
###Input format:
nothing
###Output format:
Output format of semicircle area: "area =%. 5F / N"
Semicircle arc length output format: "circumreference =%. 5F / N"
###Input example:
```in
```
###Output example:
The corresponding output is given here. For example:
```out
Area=44.12363
circumference=16.65043
```
To avoid format errors, please copy and paste the format string and prompt information given in the title directly into your program.
answer：If there is no answer, please comment
Only output, no input.
###Input format:
nothing
###Output format:
Output format of semicircle area: "area =%. 5F / N"
Semicircle arc length output format: "circumreference =%. 5F / N"
###Input example:
```in
```
###Output example:
The corresponding output is given here. For example:
```out
Area=44.12363
circumference=16.65043
```
To avoid format errors, please copy and paste the format string and prompt information given in the title directly into your program.
answer：If there is no answer, please comment
Only output, no input.