PROGRAMMING:The power of persistence
This topic requires the calculation of the ability value achieved after persistent efforts, with the first day's ability value initial as the base, the ability value improved compared with the previous day. Factor is the effort parameter, and the days of persistence is day. Let's take a look at the strength of persistence.
The calculation formula is $$result = initial times (1 + factor) ^ {day} $$, where $$result $$is the ability value after persistent efforts, $$initial $$is the initial value of ability, $$factor $$is the effort parameter, and $$day $$is the days of persistent efforts.
###Input format:
The input gives a positive real number $$initial $$, a real number $$factor $$, and a positive integer $$day $$, separated by spaces, in order on one line.
###Output format:
Output in the format of "result = capability value" in one line, where the capability value retains two decimal places. Please note that there is a space to the left and right of the equal sign.
###Input sample 1:
```in
1.0 0.01 365
```
###Output sample 1:
```out
result = 37.78
```
###Input sample 2:
```in
1.0 -0.01 365
```
###Output sample 2:
```out
result = 0.03
```
answer:If there is no answer, please comment
The calculation formula is $$result = initial times (1 + factor) ^ {day} $$, where $$result $$is the ability value after persistent efforts, $$initial $$is the initial value of ability, $$factor $$is the effort parameter, and $$day $$is the days of persistent efforts.
###Input format:
The input gives a positive real number $$initial $$, a real number $$factor $$, and a positive integer $$day $$, separated by spaces, in order on one line.
###Output format:
Output in the format of "result = capability value" in one line, where the capability value retains two decimal places. Please note that there is a space to the left and right of the equal sign.
###Input sample 1:
```in
1.0 0.01 365
```
###Output sample 1:
```out
result = 37.78
```
###Input sample 2:
```in
1.0 -0.01 365
```
###Output sample 2:
```out
result = 0.03
```
answer:If there is no answer, please comment