PROGRAMMING:Read the number into the array in order and find the number
Read 10 numbers from the keyboard and store them in an array (assuming no duplicate data), which requires the user to input from small to large. If it is found that a certain number read in is not from small to large, the number input is invalid, and the subsequent input data will continue to be read in. Then enter a number to find out which element is the number in the array (serial number starts from 1). If the number is not in the array, output "not find!".
###Input format:
In each row, read in the number stored in the array and the number to find.
###Output format:
Output the position of the number searched in the array (the serial number is calculated from 1). If it is not found, output not find!
###Input example:
```in
-10 5 9 10 20 40 80 90 100 110
eighty
```
###Output example:
```out
seven
```
###Input example:
```in
-10 5 9 10 20 40 15 30 60 90 100 110
one hundred
```
###Output example:
```out
nine
```
###Input example:
```in
-10 5 9 10 20 40 80 90 100 110
sixty
```
###Output example:
```out
Not Find!
```
answer:If there is no answer, please comment
###Input format:
In each row, read in the number stored in the array and the number to find.
###Output format:
Output the position of the number searched in the array (the serial number is calculated from 1). If it is not found, output not find!
###Input example:
```in
-10 5 9 10 20 40 80 90 100 110
eighty
```
###Output example:
```out
seven
```
###Input example:
```in
-10 5 9 10 20 40 15 30 60 90 100 110
one hundred
```
###Output example:
```out
nine
```
###Input example:
```in
-10 5 9 10 20 40 80 90 100 110
sixty
```
###Output example:
```out
Not Find!
```
answer:If there is no answer, please comment